[Nov-2021] Pass Oracle 1z0-071 Tests Engine pdf - All Free Dumps [Q105-Q121]

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[Nov-2021] Pass Oracle 1z0-071  Tests Engine pdf - All Free Dumps

Oracle Database SQL Practice Tests 2021 | Pass 1z0-071 with confidence!

NEW QUESTION 105
Examine this list of queries:
Which two statements are true?

  • A. 3 returns an error.
  • B. 2 returns the value 20.
  • C. 2 and 3 give the same result.
  • D. 1 and 4 give different results.
  • E. 1 and 4 give the same result.

Answer: B,E

 

NEW QUESTION 106
Evaluate the following two queries:

Which statement is true regarding the above two queries?

  • A. Performance would degrade in query 2.
  • B. There would be no change in performance.
  • C. Performance would improve in query 2.
  • D. Performance would improve in query 2 only if there are null values in the CUST_CREDIT_LIMIT column.

Answer: B

Explanation:
Explanation

 

NEW QUESTION 107
BOOK_SEQ is an existing sequence in your schema.
Which two CREATE TABLE commands are valid?

  • A. CREATE TABLE bookings (
    bk_id NUMBER(4) DEFAULT book_seq.NEXTVAL PRIMARY KEY,
    start_date DATE DEFAULT SYSDATE,
    end_date DATE DEFAULT SYSDATE NOT NULL);
  • B. CREATE TABLE bookings (
    bk_id NUMBER(4) NOT NULL DEFAULT book_seq.CURRVAL,
    start_date DATE NOT NULL,
    end_date DATE DEFAULT SYSDATE);
  • C. CREATE TABLE bookings (
    bk_id NUMBER(4) NOT NULL PRIMARY KEY,
    start_date DATE NOT NULL,
    end_date DATE DEFAULT SYSDATE);
  • D. CREATE TABLE bookings ( bk_id NUMBER(4),
    start_date DATE DEFAULT SYSDATE,
    end_date DATE DEFAULT (end_date >= start_date));
  • E. CREATE TABLE bookings (
    bk_id NUMBER(4) DEFAULT book_seq.CURRVAL,
    start_date DATE DEFAULT SYSDATE,
    end_date DATE DEFAULT start date);

Answer: A,C

 

NEW QUESTION 108
Examine the structure of the MEMBERS table: (Choose the best answer.)

Examine the SQL statement:
SQL > SELECT city, last_name LNAME FROM MEMBERS ORDER BY 1, LNAME DESC; What would be the result execution?

  • A. It fails because a column alias cannot be used in the ORDER BY clause.
  • B. It displays all cities in ascending order, within which the last names are further sorted in descending order.
  • C. It fails because a column number and a column alias cannot be used together in the ORDER BY clause.
  • D. It displays all cities in descending order, within which the last names are further sorted in descending order.

Answer: B

 

NEW QUESTION 109
The user SCOTT who is the owner of ORDERS and ORDER_ITEMS tables issues this GRANT command:
GRANT ALL
ON orders, order_items
TO PUBLIC;
What must be done to fix the statement?

  • A. ALL should be replaced with a list of specific privileges.
  • B. WITH GRANT OPTION should be added to the statement.
  • C. PUBLIC should be replaced with specific usernames.
  • D. Separate GRANT statements are required for the ORDERS and ORDER_ITEMS tables.

Answer: D

Explanation:
References:
http://docs.oracle.com/javadb/10.8.3.0/ref/rrefsqljgrant.html

 

NEW QUESTION 110
Which two are true about scalar subquery expressions?

  • A. They can return at most one row.
  • B. .You must enclose them in parentheses.
  • C. You cannot correlate them with a table in the parent statement
  • D. You can use them as a default value for a column.
  • E. They can return two columns.

Answer: B,C

 

NEW QUESTION 111
View the Exhibit and examine the structure of the CUSTOMERS table.

Using the CUSTOMERS table, you must generate a report that displays a credit limit increase of 15% for all customers.
Customers with no credit limit should have "Not Available" displayed.
Which SQL statement would produce the required result?

  • A. SELECT NVL(cust_credit_limit*.15, 'Not Available') "NEW CREDIT" FROM customers;
  • B. SELECT TO_CHAR(NVL(cust_credit_limit*.15, 'Not Available')) "NEW CREDIT" FROM customers;
  • C. SELECT NVL(cust_credit_limit, 'Not Available')*.15 "NEW CREDIT" FROM customers;
  • D. SELECT NVL(TO_CHAR(cust_credit_limit*.15), 'Not Available') "NEW CREDIT" FROM customers;

Answer: A

 

NEW QUESTION 112
View the Exhibit and examine the structure of the EMP table which is not partitioned and not an index- organized table. (Choose two.)

Evaluate this SQL statement:
ALTER TABLE emp
DROP COLUMN first_name;
Which two statements are true?

  • A. The FIRST_NAME column would be dropped provided it does not contain any data.
  • B. The drop of the FIRST_NAME column can be rolled back provided the SET UNUSED option is added to the SQL statement.
  • C. The FIRST_NAME column can be dropped even if it is part of a composite PRIMARY KEY provided the CASCADE option is added to the SQL statement.
  • D. The FIRST_NAME column would be dropped provided at least one column remains in the table.

Answer: D

 

NEW QUESTION 113
View the exhibit and examine the structure of the SALES, CUSTOMERS, PRODUCTS and TIMES tables.

The PROD_ID column is the foreign key in the SALES table, which references the PRODUCTS table.
Similarly, the CUST_ID and TIME_ID columns are also foreign keys in the SALES table referencing the CUSTOMERS and TIMES tables, respectively.
Evaluate the following CREATE TABLE command:
CREATE TABLE new_sales (prod_id, cust_id, order_date DEFAULT SYSDATE)
AS
SELECT prod_id, cust_id, time_id
FROM sales;
Which statement is true regarding the above command?

  • A. The NEW_SALES table would get created and all the FOREIGN KEY constraints defined on the specified columns would be passed to the new table.
  • B. The NEW_SALES table would not get created because the column names in the CREATE TABLE command and the SELECT clause do not match.
  • C. The NEW_SALES table would not get created because the DEFAULT value cannot be specified in the column definition.
  • D. The NEW_SALES table would get created and all the NOT NULL constraints defined on the specified columns would be passed to the new table.

Answer: D

 

NEW QUESTION 114
View the exhibit and examine the structure of the CUSTOMERS table.

Which two tasks would require subqueries or joins to be executed in a single statement?

  • A. listing of customers who do not have a credit limit and were born before 1980
  • B. listing of those customers, whose credit limit is the same as the credit limit of customers residing in the city 'Tokyo'.
  • C. finding the number of customers, in each city, who's marital status is 'married'.
  • D. finding the average credit limit of male customers residing in 'Tokyo' or 'Sydney'
  • E. finding the number of customers, in each city, whose credit limit is more than the average credit limit of all the customers

Answer: B,E

 

NEW QUESTION 115
View the Exhibit and examine the structure of the SALES and PRODUCTS tables. (Choose two.)

In the SALES table, PROD_ID is the foreign key referencing PROD_ID in the PRODUCTS table. You must list each product ID and the number of times it has been sold.
Examine this query which is missing a JOIN operator:
SQL > SELECT p.prod_id, count(s.prod_id)
FROM products p ______________ sales s
ON p.prod_id = s.prod_id
GROUP BY p.prod_id;
Which two JOIN operations can be used to obtain the required output?

  • A. RIGHT OUTER JOIN
  • B. FULL OUTER JOIN
  • C. LEFT OUETR JOIN
  • D. JOIN

Answer: B,C

 

NEW QUESTION 116
Evaluate the following CREATE TABLE command:

Which statement is true regarding the above SQL statement?

  • A. It would execute successfully and only ORD_ITM_IDX index would be created.
  • B. It would give an error because the USING INDEX clause is not permitted in the CREATE TABLE command.
  • C. It would give an error because the USING INDEX clause cannot be used on a composite primary.
  • D. It would execute successfully and two indexes ORD_ITM_IDX and ORD_ITM_ID_PK would be created.

Answer: A

 

NEW QUESTION 117
Examine the structure of the BOOKS_TRANSACTIONS table:

Examine the SQL statement:

Which statement is true about the outcome?

  • A. It displays details only for members who have borrowed before today with RM as TRANSACTION_TYPE.
  • B. It displays details for members who have borrowed before today with RM as TRANSACTION_TYPEand the details for members A101 or A102.
  • C. It displays details for members who have borrowed before today's date with either RM as TRANSACTION_TYPEor MEMBER_IDas A101 and A102.
  • D. It displays details for only members A101 and A102 who have borrowed before today with RM TRANSACTION_TYPE.

Answer: B

 

NEW QUESTION 118
Which three are true about privileges and roles?

  • A. PUBLIC acts as a default role granted to every user in a database.
  • B. System privileges always set privileges for an entire database.
  • C. PUBLIC can be revoked from a user.
  • D. A role is owned by the user who created it.
  • E. A user has all object privileges for every object in their schema by default.
  • F. All roles are owned by the SYS schema.
  • G. A role can contain a combination of several privileges and roles.

Answer: A,E,G

 

NEW QUESTION 119
Examine this SELECT statement and view the Exhibit to see its output:

SELECT constraints_name, constraints_type, search_condition, r_constraints_name, delete_rule, status, FROM user_constraints WHERE table_name = 'ORDERS'; Which two statements are true about the output? (Choose two.)

  • A. The R_CONSTRAINT_NAME column contains an alternative name for the constraint.
  • B. In the second column, 'c' indicates a check constraint.
  • C. The STATUS column indicates whether the table is currently in use.
  • D. The DELETE_RULE column indicates the desired state of related rows in the child table when the corresponding row is deleted from the parent table.

Answer: B,D

 

NEW QUESTION 120
View the Exhibit and examine the description for the SALES and CHANNELS tables.

You issued this SQL statement:

Which statement is true regarding the result? (Choose the best answer.)

  • A. The statement will fail because a subquery cannot be used in a VALUES clause.
  • B. The statement will fail because the subquery in the VALUES clause is not enclosed within single quotation marks.
  • C. The statement will execute and a new row will be inserted in the SALES table.
  • D. The statement will fail because the VALUES clause is not required with the subquery.

Answer: C

 

NEW QUESTION 121
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